reactants products
h 4 h 4
o 2 o 2
__h₂ + __o₂ → __h₂o
2 reactants products
p p
o o
__p₄ + __o₂ → __p₂o₃
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Question

Accepted Answer

# Explanation:
## Step1: Balance hydrogen atoms
For the reaction $H_2 + O_2
ightarrow H_2O$, in $H_2$ there are 2 H atoms per molecule, and in $H_2O$ there are also 2 H atoms per molecule. Given 4 H atoms in reactants (from $4H_2$), in products, for $H_2O$, since each $H_2O$ has 2 H atoms, the coefficient of $H_2O$ is $\frac{4}{2}=2$. But wait, let's check oxygen. In reactants, from $2O_2$ (2 molecules, each with 2 O atoms) there are $2\times2 = 4$ O atoms. In products, each $H_2O$ has 1 O atom. If the coefficient of $H_2O$ is 4 (because $4H_2O$ has $4\times1=4$ O atoms). So the balanced equation is $4H_2+2O_2 = 4H_2O$

## Step2: Balance phosphorus and oxygen atoms
For the reaction $P_4+O_2
ightarrow P_2O_3$. In $P_4$ there are 4 P atoms per molecule, and in $P_2O_3$ there are 2 P atoms per molecule. Let the coefficient of $P_4$ be $x$ and of $P_2O_3$ be $y$. For P - atoms: $4x = 2y$, assume $x = 1$, then $y=2$. For O - atoms: in $O_2$ (let the coefficient be $z$)  and $P_2O_3$ (coefficient $y = 2$, each $P_2O_3$ has 3 O atoms). So $2z=2\times3$, $z = 3$. The balanced equation is $P_4+3O_2 = 2P_2O_3$

# Answer:
1. $4H_2+2O_2 = 4H_2O$
2. $P_4+3O_2 = 2P_2O_3$

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QUESTION IMAGE

Question

Explanation:

Step1: Balance hydrogen atoms

Step2: Balance phosphorus and oxygen atoms

Answer: