Question

question
if the volume of a gas is kept constant and the temperature (in kelvin) is doubled, the pressure will
select the correct answer below:
double
quadruple
be cut in half
be cut in one fourth

Explanation:

Step1: State Gay - Lussac's Law

Gay - Lussac's Law is \(P = kT\) (where \(P\) is pressure, \(T\) is temperature in Kelvin, and \(k\) is a constant when volume \(V\) and amount of gas \(n\) are constant).

Step2: Analyze the effect of doubling temperature

Let the initial pressure be \(P_1=kT_1\). If \(T_2 = 2T_1\), then \(P_2=kT_2\). Substitute \(T_2 = 2T_1\) into the equation: \(P_2=k(2T_1)=2(kT_1)\). Since \(P_1 = kT_1\), we have \(P_2 = 2P_1\).

So when the volume of a gas is kept constant and the temperature (in Kelvin) is doubled, the pressure will double.

Answer:

double