Question

question #5
use valence bond theory to explain the bonding in h₂cch₂.
the σ bond between the carbon atoms is due to overlap of
the π bonds between the carbon atoms are due to overlap of

question #6
draw the molecular orbital diagram for ne₂, then use it to answer the following questions.
how many electrons are in each of these ne₂ molecular orbitals?
σ₂p π₂p σ₂p π₂p
what is the bond order for ne₂?
what type of substance is ne₂?

Explanation:

Step1: Determine the bond order formula

The bond order formula is \( \text{Bond Order}=\frac{1}{2}(N_{b}-N_{a})\), where \(N_{b}\) is the number of electrons in bonding orbitals and \(N_{a}\) is the number of electrons in antibonding orbitals.

Step2: Analyze the molecular orbital configuration of \(Ne_{2}\)

Neon has an atomic number of 10. So, \(Ne_{2}\) has \(2\times10 = 20\) electrons. The molecular orbital configuration of \(Ne_{2}\) is \(\sigma_{1s}^{2}\sigma_{1s}^{*2}\sigma_{2s}^{2}\sigma_{2s}^{*2}\sigma_{2p}^{2}\pi_{2p}^{4}\pi_{2p}^{*4}\sigma_{2p}^{*2}\).
The number of bonding electrons \(N_{b}= 8\) (from \(\sigma_{1s}^{2},\sigma_{2s}^{2},\sigma_{2p}^{2},\pi_{2p}^{4}\)) and the number of antibonding electrons \(N_{a}= 8\) (from \(\sigma_{1s}^{*2},\sigma_{2s}^{*2},\pi_{2p}^{*4},\sigma_{2p}^{*2}\)).

Step3: Calculate the bond order

Substitute \(N_{b} = 8\) and \(N_{a}=8\) into the bond - order formula:

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Answer:

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