Question

question 1
in a solution made by dissolving nacl in water, the solute is:
nacl
na+
cl-
h2o
question 2
if you weighed out 25.0 g of nacl, how many moles of nacl would you have? (mm nacl = 58.44 g/mol)
1460 g
0.428 g
1.14 g
83.44 g

Explanation:

Step1: Recall the formula for moles

The formula for calculating moles ($n$) is $n=\frac{m}{M}$, where $m$ is the mass and $M$ is the molar mass.

Step2: Substitute the given values

Given $m = 25.0\ g$ and $M=58.44\ g/mol$. Then $n=\frac{25.0\ g}{58.44\ g/mol}\approx0.428\ mol$.

Answer:

0.428 mol