Question

question 7
1 pts
you wish to prepare 0.037 m kclo3 from a stock solution of potassium chlorate that is 1.45 m. how
many milliliters of the stock solution do you need to make 10.00 ml of 0.037 m kclo3? report the
volume to 2 sig figs and do not include units in your answer.

question 8
2 pts
what is the elemental composition of acetic acid, hc2h3o2? report the mass percent of each element
to 4 significant digits and do not include units.
% h
% c
% o

Explanation:

Step1: Use dilution formula

The dilution formula is \(M_1V_1 = M_2V_2\), where \(M_1 = 1.45\ M\), \(M_2=0.037\ M\), \(V_2 = 10.00\ mL\). We need to find \(V_1\).

Step2: Rearrange the formula

From \(M_1V_1 = M_2V_2\), we can solve for \(V_1\) as \(V_1=\frac{M_2V_2}{M_1}\).

Step3: Substitute the values

Substitute \(M_1 = 1.45\), \(M_2 = 0.037\), \(V_2 = 10.00\) into the formula: \(V_1=\frac{0.037\times10.00}{1.45}\).

Step4: Calculate the value

\(V_1=\frac{0.37}{1.45}\approx0.26\)

Answer:

0.26