Question

question 2 (5 points)
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how many joules must be added to a 1000 g iron skillet to increase its temperature from 25°c to 250°c? the specific heat of iron is 0.449 j/g°c.
a) 112,250 j
b) 101,025 j
c) 50,000 j
d) 449 j

Explanation:

Step1: Recall the heat formula

The formula for heat energy \( Q \) is \( Q = mc\Delta T \), where \( m \) is mass, \( c \) is specific heat, and \( \Delta T \) is the change in temperature.

Step2: Calculate the change in temperature

\( \Delta T = T_2 - T_1 = 250^\circ\text{C} - 25^\circ\text{C} = 225^\circ\text{C} \)

Step3: Substitute values into the formula

Given \( m = 1000\ \text{g} \), \( c = 0.449\ \text{J/g}^\circ\text{C} \), and \( \Delta T = 225^\circ\text{C} \), we have:
\( Q = 1000\ \text{g} \times 0.449\ \text{J/g}^\circ\text{C} \times 225^\circ\text{C} \)
\( Q = 1000 \times 0.449 \times 225 \)
\( Q = 1000 \times 101.025 \)
\( Q = 101025\ \text{J} \)

Answer:

B) 101,025 J