Question

question 2 (2 points)
how many liters of a 2.00 m solution are needed to have 4.00 moles?
1 l
(2 mol)(---------) = 3 mol
4 mol
a. 0 b. 1 c. 2 d. 3 e. 4 f. 5
g. 6 h. 234 i. 58.44 j. 100. k. 1.71
l. 0.856 m. 10.0

Explanation:

Step1: Recall the formula for molarity

Molarity ($M$) is defined as $M=\frac{n}{V}$, where $n$ is the number of moles and $V$ is the volume in liters. Rearranging for $V$ gives $V = \frac{n}{M}$.

Step2: Substitute the given values

We are given $n = 4.00$ mol and $M=2.00$ M (mol/L). So $V=\frac{4.00\space mol}{2.00\space mol/L}$.

Step3: Calculate the volume

$V = 2.00$ L.

For the second part (the formula - based on the molarity formula $M=\frac{n}{V}$ or $n = M\times V$). If we consider $n = M\times V$, when $M = 2.00$ mol/L and $V$ is the volume (in L). But if we rewrite it as $V=\frac{n}{M}$, in the given $( \text{__2__ mol})(\text{--------})=\text{__3__ mol}$, using $V=\frac{n}{M}$ (or $n = M\times V$), if we assume the first blank (2) is $n = 4.00$ mol, the second blank is $\frac{1}{M}=\frac{1}{2.00\space mol/L}$ (to get volume in L, but since the final unit is mol, there might be a mis - interpretation. However, if we consider the first formula $n = M\times V$, then $(2.00\space mol/L)(V)=4.00\space mol$.

Answer:

1. C. 2
2. E. 4
3. E. 4
4. E. 4