Question

question 7 (0.5 points)
the following shape has 1 reds, 2 are bonding and 3 are nonbonding. the shape is called 4 and the bond angles are 5.
a. 0 b. 1 c. 2 d. 3 e. 4 f. 5 g. 6 h. diatomic
i. linear j. planar trigonal k. bent l. tetrahedral m. pyramidal
n. hexahedral o. seesaw p. t - shape q. octahedral r. square pyramidal
s. square planar t. 90° u. 109.5° v. 120° w. 180°
x. 90°, 120°, and 180° y. 90° and 180°

Explanation:

1. REDs (Region of Electron Density): Count the total electron - density regions (bonding + non - bonding). In the given molecule, there are 4 regions (2 bonding to green atoms, 2 non - bonding on blue atoms).
2. Bonding REDs: Count the number of bonds. There are 2 bonds (to green atoms).
3. Non - bonding REDs: Count the number of lone pairs. There are 2 lone pairs (on blue atoms).
4. Shape: For a molecule with 4 electron - density regions (2 bonding, 2 non - bonding), the molecular shape is bent.
5. Bond angles: For a bent molecule with 4 electron - density regions (based on VSEPR theory, similar to water - like structure), the bond angle is approximately \(109.5^{\circ}\) (considering the tetrahedral electron - pair geometry with two lone pairs).

Answer:

1. E
2. C
3. C
4. K
5. U