Question

question 5 (1 point)
write the chemical formula for each ionic compound
thallium (iii) bromide

question 6 (1 point)
write the chemical formula for each ionic compound
mercury (i) oxide

Explanation:

Step1: Determine the ions

• Thallium (III) has a charge of \(+3\) (\(Tl^{3+}\)).
• Bromide ion has a charge of \(-1\) (\(Br^{-}\)).
• Mercury (I) exists as \(Hg_{2}^{2+}\) (a diatomic ion with a charge of \(+2\) overall for the two - mercury unit).
• Oxide ion has a charge of \(-2\) (\(O^{2 -}\)).

Step2: Apply the criss - cross rule

• For thallium (III) bromide:
• The charge of \(Tl^{3+}\) is \(+3\) and the charge of \(Br^{-}\) is \(-1\).
• Using the criss - cross rule (the magnitude of the charge of one ion becomes the subscript of the other ion), we get \(TlBr_{3}\).
• For mercury (I) oxide:
• The charge of \(Hg_{2}^{2+}\) is \(+2\) and the charge of \(O^{2 -}\) is \(-2\).
• Using the criss - cross rule (the magnitude of the charge of one ion becomes the subscript of the other ion), the formula is \(Hg_{2}O\).

Answer:

Question 5: \(TlBr_{3}\)
Question 6: \(Hg_{2}O\)