Question

question 3 · 1 point
what will happen to the volume of a gas if its absolute temperature triples (increases by a factor of three) as the amount of gas and the pressure are held constant?
select the correct answer below:
the volume will decrease by a factor of three.
the volume will triple (increase by a factor of three).
the volume will double (increase by a factor of two).
the volume will be cut in half (decrease by a factor of two).

Explanation:

Step1: Recall Charles's Law

Charles's Law is \(V = kT\) (where \(V\) is volume, \(T\) is absolute temperature, and \(k\) is a constant when pressure \(P\) and amount of gas \(n\) are constant).

Step2: Analyze the change

Let the initial volume be \(V_1= kT_1\). If \(T_2 = 3T_1\), then \(V_2= kT_2\). Substitute \(T_2 = 3T_1\) into \(V_2\), we get \(V_2= k\times(3T_1)=3(kT_1)\). Since \(V_1 = kT_1\), then \(V_2 = 3V_1\). So the volume triples.

Answer:

The volume will triple (increase by a factor of three).