Question

question 8 (1 point)
use the molar mass of ca3(po3)2 to calculate the moles in 10.0 g of calcium phosphite. choose the closest answer.
(10.0 g cp)(--------) = 1mol cp
a. 1.112 x 1010 b. 3.983 x 103 c. 2.394 x 104 d. 0.03595 e. 2.898
f. 2.162 x 1022 g. 0.3451 h. 1.675 x 1025 i. 1.853 x 109 j. 34.51
k. 1.436 x 105 l. 2.782 x 103 m. 3.996 x 107 n. 5.969 x 10-26
o. 5.969 x 1026 p. 3.595 x 10-1 q. 2.782 x 10-3

Explanation:

Step1: Calculate molar mass of \(Ca_3(PO_3)_2\)

Atomic masses: \(Ca = 40.08\space g/mol\), \(P = 30.97\space g/mol\), \(O = 16.00\space g/mol\)

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Step2: Calculate moles using \(n=\frac{m}{M}\)

Given \(m = 10.0\space g\), \(M=278.18\space g/mol\)

$$n=\frac{10.0}{278.18}\approx0.03595\space mol$$

Answer:

D. \(0.03595\)