Question

question 2 (1 point) saved listen which of the following compounds would form only london dispersion forces with an identical compound? hcn co₂ ch₃och₃ c₃h₇oh cacl₂

Explanation:

• London dispersion forces are the weakest intermolecular forces and exist in all molecules. But for a compound to have only London dispersion forces with an identical compound, it must be non - polar.
• \(HCN\) is a polar molecule (due to the difference in electronegativity between \(H\), \(C\), and \(N\) and its linear but asymmetric structure in terms of charge distribution).
• \(CO_{2}\) is a non - polar molecule (linear structure \(O = C=O\), the bond dipoles cancel each other out).
• \(CH_{3}OCH_{3}\) (dimethyl ether) is a polar molecule (the oxygen atom has a higher electronegativity, creating a dipole).
• \(C_{3}H_{7}OH\) (propanol) is a polar molecule (due to the \(O - H\) bond which is highly polar and the overall molecular structure).
• \(CaCl_{2}\) is an ionic compound (the force between \(Ca^{2 +}\) and \(Cl^{-}\) is ionic bonding, not London dispersion forces).

Answer:

\(CO_{2}\)