Question

question 5
the oxidation number of mn in kmno₄ is
a 7+
b 7-
c 8+
d 5+

Explanation:

Step1: Oxidation number of K and O

In \(KMnO_4\), the oxidation number of \(K\) (potassium) is \(+ 1\) (since it is in group 1 of the periodic table and has a stable \(+1\) oxidation state). The oxidation number of \(O\) (oxygen) in most compounds is \(-2\).

Step2: Set up the equation

Let the oxidation number of \(Mn\) be \(x\). For a neutral compound \(KMnO_4\), the sum of oxidation numbers is \(0\). So, \((+1)+x + 4\times(-2)=0\)

Step3: Solve the equation

$$
LATEXBLOCK0
$$

Answer:

A. \(7+\)