Question

question one

\

$$\begin{tabular}{|c|c|c|} \\hline & structural formula & iupac (systematic) name \\\\ \\hline a & \\(\\text{ch}_2\\text{=chch}_2\\text{ch}_2\\text{ch}_2\\text{ch}_3\\) & \\\\ \\hline b & & \\begin{tabular}{c} pentan-1-amine \\\\ (1-aminopentane) \\end{tabular}$$

\\\\
\hline
c & \

$$\begin{array}{c} \\text{ch}_3 \\\\ | \\\\ \\text{ch}_3-\\text{c}-\\text{ch}_3 \\\\ | \\\\ \\text{cl} \\end{array}$$

& \\\\
\hline
d & & 3-methylbutanoic acid \\\\
\hline
\end{tabular}

(a) (i) complete the table by either drawing the structural formula or giving the iupac (systematic) name.

(ii) compound c is classified as a tertiary haloalkane. explain this classification.

Explanation:

Determine IUPAC name for A and structural formula for B

$$
LATEXBLOCK0
$$

Determine IUPAC name for C and structural formula for D

$$
LATEXBLOCK1
$$

Explain classification of Compound C

$$
LATEXBLOCK2
$$

Answer:

Question (a)(i)

	Structural formula	IUPAC (systematic) name
B	\(\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{CH}_2\text{NH}_2\)	pentan-1-amine (1-aminopentane)
C	\(\text{(CH}_3\text{)}_3\text{CCl}\)	2-chloro-2-methylpropane
D	\(\text{(CH}_3\text{)}_2\text{CHCH}_2\text{COOH}\)	3-methylbutanoic acid

Question (a)(ii)

Compound C is classified as a tertiary haloalkane because the carbon atom bonded to the chlorine atom is directly attached to three other carbon atoms (methyl groups).