Question

question 2 (4 marks)
in the lab you were asked to calculate a % difference between your trials. a student measures the following volumes of naoh: 15.76 ml, 16.13 ml, 15.91 ml. calculate the % difference of the three trials, determine if all three fall within the expected range, and determine which trial should be discarded, if any. determine the average volume of naoh used (remember to consider only valid values).

Explanation:

Step1: Identify max/min values

Max = 16.13 mL, Min = 15.76 mL

Step2: Calculate % difference

% difference = $\frac{Max - Min}{(Max + Min)/2} \times 100$
Substitute values: $\frac{16.13 - 15.76}{(16.13 + 15.76)/2} \times 100 = \frac{0.37}{15.945} \times 100 ≈ 2.32\%$

Step3: Check validity (no range given)

Assume all valid since no expected range is provided.

Step4: Calculate average volume

Average = $\frac{15.76 + 16.13 + 15.91}{3} = \frac{47.8}{3} ≈ 15.93$ mL

Answer:

% difference ≈ 2.32%, average volume ≈ 15.93 mL
(Note: Validity check requires an expected range, which is not provided here.)