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question 3 fill in the gaps in the following table, assuming each colum…
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Question

question 3
fill in the gaps in the following table, assuming each column
represents a neutral atom.

symbolcdsrsekru
neutrons64584945143
electron4838383692
mass no112878781235

question 4
draw the lewis structure for the following compounds. note: use
the given information (electronegativity chart) to indicate whether
the bonds in the compounds are polar or non - polar, covalent or
ionic, and draw the appropriate structure.
a) h₂o b) chcl₃ c) cl₂ d) nh₃ e) mgbr₂

  1. identify the more polar bond in each of the following pairs.

a) h - f and h - cl e) c - h and n - h
b) n - o and c - o f) s - o and p - o
c) s - h and o - h g) c - n and n - n
d) p - cl and s - cl

Explanation:

Step1: Recall Atomic Structure Basics

For a neutral atom, \( \text{Protons} = \text{Electrons} \), and \( \text{Mass Number} = \text{Protons} + \text{Neutrons} \), \( \text{Neutrons} = \text{Mass Number} - \text{Protons} \).

Step2: Analyze Each Column (Cd, Sr, Se, Kr, U)

Column 1: Cd (Cadmium)
  • Protons: Atomic number of Cd is 48, so Protons = 48.
  • Neutrons: Mass No - Protons = 112 - 48 = 64 (matches given Neutrons).
  • Electrons: Equal to Protons, so 48.
Column 2: Sr (Strontium)
  • Protons: Atomic number of Sr is 38, so Protons = 38.
  • Neutrons: Mass No - Protons = 87 - 38 = 49? Wait, given Neutrons is 58? Wait, maybe typo? Wait, Mass No is 87, Protons 38, so Neutrons = 87 - 38 = 49. But given Neutrons is 58? Wait, maybe symbol error? Wait, if Protons 38, Electrons 38 (neutral), Mass No = 38 + 58 = 96? Wait, maybe original table has errors, but following formula: Electrons = Protons = 38 (since neutral).
Column 3: Se (Selenium)
  • Protons: Atomic number of Se is 34? Wait, no, given Protons 38? Wait, no, table says Protons 38? Wait, no, original table: Se row, Protons? Wait, table columns: Symbol, Protons, Neutrons, Electron, Mass No. Let's re-express:
SymbolProtonsNeutronsElectronMass No
(Sr?)3858?87
Se?4938?
Kr?363881
U92??236

Wait, for Se: Electrons = 38 (given), so Protons = 38 (neutral). Then Mass No = 38 + 49 = 87. Wait, but Kr: Electrons 38, so Protons 38? No, Kr atomic number is 36. Wait, confusion. Let's correct:

For a neutral atom: \( Z = \text{Protons} = \text{Electrons} \), \( A = Z + N \) (N=Neutrons).

So:

  1. Cd: \( Z = 48 \) (Protons), \( N = 64 \), \( A = 48 + 64 = 112 \), \( e^- = 48 \) (correct).
  1. Sr: \( Z = 38 \) (Protons), \( e^- = 38 \) (neutral), \( A = 38 + 58 = 96 \) (but table says Mass No 87? Maybe error, but \( e^- = 38 \)).
  1. Se: \( e^- = 38 \) (neutral), so \( Z = 38 \) (Protons), \( N = 49 \), \( A = 38 + 49 = 87 \).
  1. Kr: \( e^- = 38 \)? No, Kr \( Z = 36 \), so \( e^- = 36 \). Wait, table says Electron 38, so Protons 38, \( N = 36 \), \( A = 38 + 36 = 74 \), but table says Mass No 81. Error.
  1. U: \( Z = 92 \) (Protons), \( e^- = 92 \) (neutral), \( N = 236 - 92 = 144 \), \( A = 236 \).

Assuming table has some typos, but following the formula \( \text{Electrons} = \text{Protons} \) (neutral), so:

  • Column 2 (Sr): Electrons = Protons = 38.
  • Column 3 (Se): Protons = Electrons = 38, Mass No = 38 + 49 = 87.
  • Column 4 (Kr): Protons = Electrons = 38? No, Kr is 36. But table says Electron 38, so Protons 38, Neutrons = 81 - 38 = 43, but table says Neutrons 36. Error.
  • Column 5 (U): Electrons = Protons = 92, Neutrons = 236 - 92 = 144.

So filling the gaps (assuming neutral, so Electrons = Protons):

SymbolProtonsNeutronsElectronMass No
Sr38493887(if Neutrons 49, else if Neutrons 58, Mass No 96)
Se38493887
Kr38433881(if Mass No 81, Neutrons=81-38=43)
U9214492236

But original table has Se Neutrons 49, Electron 38, so Protons 38, Mass No 38+49=87.

Sr: Protons 38, Electron 38, Neutrons=87-38=49 (but table say…

Answer:

Filling the gaps (assuming neutral atoms, \( \text{Electrons} = \text{Protons} \), \( \text{Mass No} = \text{Protons} + \text{Neutrons} \)):

  • Cd: Electrons = 48 (matches Protons 48), Mass No = 48 + 64 = 112 (matches).
  • Sr: Electrons = 38 (equal to Protons 38), Neutrons = 87 - 38 = 49 (or if Neutrons=58, Mass No=38+58=96).
  • Se: Protons = 38 (equal to Electrons 38), Mass No = 38 + 49 = 87.
  • Kr: Protons = 38 (equal to Electrons 38), Neutrons = 81 - 38 = 43 (or if Neutrons=36, Mass No=38+36=74).
  • U: Electrons = 92 (equal to Protons 92), Neutrons = 236 - 92 = 144.
Question 4: Lewis Structures & Bond Polarity
a) \( \text{H}_2\text{O} \)
  • Electronegativity: O (3.5) > H (2.1), so bonds are polar covalent.
  • Lewis Structure: O in center, two single bonds to H, two lone pairs on O: \( \text{H}-\text{O}-\text{H} \) (with two lone pairs on O).
b) \( \text{CHCl}_3 \)
  • Electronegativity: Cl (3.0) > C (2.5) > H (2.1), so C-Cl bonds are polar covalent, C-H is nonpolar covalent.
  • Lewis Structure: C in center, single bonds to H, three Cl atoms, no lone pairs on C.
c) \( \text{Cl}_2 \)
  • Electronegativity: Cl (3.0) = Cl (3.0), so nonpolar covalent.
  • Lewis Structure: \( \text{Cl}::\text{Cl} \) (single bond, three lone pairs on each Cl).
d) \( \text{NH}_3 \)
  • Electronegativity: N (3.0) > H (2.1), so bonds are polar covalent.
  • Lewis Structure: N in center, three single bonds to H, one lone pair on N: \( \text{H}-\text{N}-\text{H} \) (with one lone pair on N), \( \text{H} \) below.
e) \( \text{MgBr}_2 \)
  • Electronegativity: Br (2.8) < Mg (1.2), so ionic (electron transfer from Mg to Br).
  • Lewis Structure: \( \text{Mg}^{2+} + 2\text{Br}^- \) (Br⁻ with eight electrons, Mg²⁺ with no valence electrons).
Question 5: More Polar Bond (Based on Electronegativity Difference, \( \Delta \chi \))

Polarity depends on \( \Delta \chi = |\chi_A - \chi_B| \); larger \( \Delta \chi \) = more polar.

a) \( \text{H-F} \) vs \( \text{H-Cl} \)
  • \( \chi(\text{F}) = 4.0 \), \( \chi(\text{Cl}) = 3.0 \), \( \chi(\text{H}) = 2.1 \).
  • \( \Delta \chi(\text{H-F}) = 4.0 - 2.1 = 1.9 \); \( \Delta \chi(\text{H-Cl}) = 3.0 - 2.1 = 0.9 \).
  • More polar: \( \text{H-F} \).
b) \( \text{N-O} \) vs \( \text{C-O} \)
  • \( \chi(\text{N}) = 3.0 \), \( \chi(\text{C}) = 2.5 \), \( \chi(\text{O}) = 3.5 \).
  • \( \Delta \chi(\text{N-O}) = 3.5 - 3.0 = 0.5 \); \( \Delta \chi(\text{C-O}) = 3.5 - 2.5 = 1.0 \).
  • More polar: \( \text{C-O} \).
c) \( \text{S-H} \) vs \( \text{O-H} \)
  • \( \chi(\text{S}) = 2.5 \), \( \chi(\text{O}) = 3.5 \), \( \chi(\text{H}) = 2.1 \).
  • \( \Delta \chi(\text{S-H}) = 2.5 - 2.1 = 0.4 \); \( \Delta \chi(\text{O-H}) = 3.5 - 2.1 = 1.4 \).
  • More polar: \( \text{O-H} \).
d) \( \text{P-Cl} \) vs \( \text{S-Cl} \)
  • \( \chi(\text{P}) = 2.1 \), \( \chi(\text{S}) = 2.5 \), \( \chi(\text{Cl}) = 3.0 \).
  • \( \Delta \chi(\text{P-Cl}) = 3.0 - 2.1 = 0.9 \); \( \Delta \chi(\text{S-Cl}) = 3.0 - 2.5 = 0.5 \).
  • More polar: \( \text{P-Cl} \).
e) \( \text{C-H} \) vs \( \text{N-H} \)
  • \( \chi(\text{C}) = 2.5 \), \( \chi(\text{N}) = 3.0 \), \( \chi(\text{H}) = 2.1 \).
  • \( \Delta \chi(\text{C-H}) = 2.5 - 2.1 = 0.4 \); \( \Delta \chi(\text{N-H}) = 3.0 - 2.1 = 0.9 \).
  • More polar: \( \text{N-H} \).
f) \( \text{S-O} \) vs \( \text{P-O} \)
  • \( \chi(\text{S}) = 2.5 \), \( \chi(\text{P}) = 2.1 \), \( \chi(\text{O}) = 3.5 \).
  • \( \Delta \chi(\text{S-O}) = 3.5 - 2.5 = 1.0 \); \( \Delta \chi(\text{P-O}) = 3.5 - 2.1 = 1.4 \).
  • More polar: \( \text{P-O} \).
g) \( \text{C-N} \) vs \( \text{N-N} \)
  • \( \chi(\text{C}) = 2.5 \), \( \chi(\text{N}) = 3.0 \).
  • \( \Delta \chi(\text{C-N}) = 3.0 - 2.5 = 0.5 \); \( \Delta \chi(\text{N-N}) = 0 \) (nonpolar).
  • More polar: \( \text{C-N} \).