Question

question 3 extra credit
what is the mass of sodium chloride (salt) formed when 50.1 grams of sodium reacts with 32 grams of chlorine gas?
unit
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question 4
given the following equation:
2 n₂ (g) + 3 h₂ (g) → 2 nh₃ (g)
how many moles of nh₃ are produced if 15 mol of n₂ reacts?
mol nh₃
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question 5
given the following equation:
4 nh₃ (g) + 5 o₂ (g) → 4 no (g) + 6 h₂o (l)
how many moles of nh₃ is required to produce 5.6 mol of h₂o?
mol nh₃

Explanation:

Question 3

Step1: Write the reaction equation

Sodium (Na) reacts with chlorine gas ($\ce{Cl2}$) to form sodium chloride (NaCl). The balanced chemical equation is: $\ce{2Na + Cl2 -> 2NaCl}$

Step2: Calculate moles of reactants

Molar mass of Na = 22.99 g/mol, moles of Na = $\frac{50.1\ \text{g}}{22.99\ \text{g/mol}} \approx 2.18\ \text{mol}$
Molar mass of $\ce{Cl2}$ = 70.90 g/mol, moles of $\ce{Cl2}$ = $\frac{32\ \text{g}}{70.90\ \text{g/mol}} \approx 0.451\ \text{mol}$

Step3: Determine limiting reactant

From the equation, 2 mol Na reacts with 1 mol $\ce{Cl2}$.
Moles of Na required for 0.451 mol $\ce{Cl2}$: $2 \times 0.451 = 0.902\ \text{mol}$ (but we have 2.18 mol Na, so $\ce{Cl2}$ is limiting).

Step4: Calculate moles of NaCl formed

From the equation, 1 mol $\ce{Cl2}$ produces 2 mol NaCl.
Moles of NaCl = $2 \times 0.451 = 0.902\ \text{mol}$

Step5: Calculate mass of NaCl

Molar mass of NaCl = 58.44 g/mol, mass = $0.902\ \text{mol} \times 58.44\ \text{g/mol} \approx 52.7\ \text{g}$

Step1: Identify mole ratio from equation

The balanced equation is $\ce{2N2(g) + 3H2(g) -> 2NH3(g)}$.
Mole ratio of $\ce{N2}$ to $\ce{NH3}$ is $2:2$ (or $1:1$).

Step2: Calculate moles of $\ce{NH3}$

If 15 mol of $\ce{N2}$ reacts, moles of $\ce{NH3}$ = 15 mol (since ratio is 1:1).

Step1: Identify mole ratio from equation

The balanced equation is $\ce{4NH3(g) + 5O2(g) -> 4NO(g) + 6H2O(l)}$.
Mole ratio of $\ce{NH3}$ to $\ce{H2O}$ is $4:6$ (simplify to $2:3$).

Step2: Set up proportion

Let $x$ = moles of $\ce{NH3}$.
$\frac{4}{6} = \frac{x}{5.6\ \text{mol}}$

Step3: Solve for $x$

$x = \frac{4 \times 5.6}{6} \approx 3.73\ \text{mol}$

Answer:

52.7 grams (unit: grams)

Question 4