Question

question 6. calculate the atomic mass of titanium. the five titanium isotopes have atomic masses and relative abundances of 45.953 amu (8.00%), 46.952 amu (7.30%), 47.948 amu (73.80%), 48.948 amu (5.50%), and 49.945 amu (5.40%)

Explanation:

Step1: Convert percentages to decimals

$8.00\% = 0.08$, $7.30\%=0.073$, $73.80\% = 0.738$, $5.50\%=0.055$, $5.40\% = 0.054$

Step2: Multiply each isotope's mass by its relative - abundance

For the first isotope: $45.953\times0.08 = 3.67624$
For the second isotope: $46.952\times0.073=3.427496$
For the third isotope: $47.948\times0.738 = 35.385624$
For the fourth isotope: $48.948\times0.055 = 2.69214$
For the fifth isotope: $49.945\times0.054=2.69703$

Step3: Sum up the results

$3.67624 + 3.427496+35.385624 + 2.69214+2.69703=47.87853$

Answer:

$47.88$ amu (rounded to two decimal places)