Question

question 77 (1 point) listen if h⁺ is 1 × 10⁻⁷, the solution has : 1) oh⁻ = 1 × 10⁻⁷ 2) ph of 7.0 3) neutral ph 4) all of the above

Explanation:

Step1: Recall ion product of water

The ion product of water, \(K_w = [H^+][OH^-] = 1\times10^{-14}\) at 25°C.

Step2: Calculate \([OH^-]\)

Given \([H^+] = 1\times10^{-7}\), substitute into \(K_w\):
\([OH^-]=\frac{K_w}{[H^+]}=\frac{1\times10^{-14}}{1\times10^{-7}} = 1\times10^{-7}\).

Step3: Calculate pH

\(pH = -\log[H^+]=-\log(1\times10^{-7}) = 7.0\).

Step4: Determine solution nature

A pH of 7.0 means the solution is neutral (equal \([H^+]\) and \([OH^-]\)).

Answer:

1. All of the above