Question

question 60 (1 point)
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the empirical formula for the compound c₄₂h₇cl₁₄o₂₈ is:

1. c₆hcl₂o₄
2. c₂h₂cl₂o₂
3. c₆h₂cl₂o
4. c₁₂h₄cl₄o₂

Explanation:

Step1: Find GCD of subscripts

Find the greatest common divisor (GCD) of 42, 7, 14, 28. The factors of 7: 1,7; 42÷7=6, 14÷7=2, 28÷7=4. So GCD is 7.

Step2: Divide each subscript by GCD

For C: \( \frac{42}{7} = 6 \), H: \( \frac{7}{7} = 1 \), Cl: \( \frac{14}{7} = 2 \), O: \( \frac{28}{7} = 4 \). So empirical formula is \( C_6HCl_2O_4 \).

Answer:

1. \( C_6HCl_2O_4 \)