Question

question 53 (2 points)
how many electrons are in a rubidium ion (rb^+)?
blank 1:

Explanation:

Step1: Determine the atomic number of rubidium

The atomic number of rubidium (Rb) is 37. This means a neutral Rb atom has 37 electrons.

Step2: Analyze the ion formation

The ion \(Rb^{+}\) is formed by the loss of one electron from a neutral Rb atom.

Step3: Calculate the number of electrons in \(Rb^{+}\)

If a neutral Rb atom has 37 electrons and it loses one electron to form \(Rb^{+}\), then the number of electrons in \(Rb^{+}\) is \(37 - 1=36\).

Answer:

36