Question

question 20
1 pts
when the reaction shown is balanced, there are ____ atoms of oxygen and ____ atoms of hydrogen on each side.
(nh4)2so4 (aq) + ba(c2h3o2)2 (aq) → baso4 (s) + nh4c2h3o2 (aq)
6; 11
16; 18
8; 14
16; 28
4; 7

Explanation:

Step1: Balance the chemical equation

The un - balanced equation is \((NH_{4})_{2}SO_{4}(aq)+Ba(C_{2}H_{3}O_{2})_{2}(aq)\to BaSO_{4}(s)+NH_{4}C_{2}H_{3}O_{2}(aq)\)
We can balance it by putting a coefficient of \(2\) in front of \(NH_{4}C_{2}H_{3}O_{2}\). The balanced equation is \((NH_{4})_{2}SO_{4}(aq)+Ba(C_{2}H_{3}O_{2})_{2}(aq)\to BaSO_{4}(s)+2NH_{4}C_{2}H_{3}O_{2}(aq)\)

Step2: Count the oxygen atoms

• In \((NH_{4})_{2}SO_{4}\), the number of \(O\) atoms: \(4\)
• In \(Ba(C_{2}H_{3}O_{2})_{2}\), the number of \(O\) atoms: \(2\times2 = 4\)
• Total \(O\) atoms on the left - hand side: \(4 + 4=8\)
• In \(BaSO_{4}\), the number of \(O\) atoms: \(4\)
• In \(2NH_{4}C_{2}H_{3}O_{2}\), the number of \(O\) atoms: \(2\times2 = 4\)
• Total \(O\) atoms on the right - hand side: \(4+4 = 8\)

Step3: Count the hydrogen atoms

• In \((NH_{4})_{2}SO_{4}\), the number of \(H\) atoms: \(2\times4=8\)
• In \(Ba(C_{2}H_{3}O_{2})_{2}\), the number of \(H\) atoms: \(2\times3 = 6\)
• Total \(H\) atoms on the left - hand side: \(8 + 6=14\)
• In \(2NH_{4}C_{2}H_{3}O_{2}\), the number of \(H\) atoms: \(2\times(4 + 3)=14\)

Answer:

C. \(8;14\)