Question

question 20 (1 point)
a solution has the 23.22% mass/volume of a particular solvent what is the mass of solute dissolved in 2.5 liter of solvent?
232.2 g
0.232 g
580.5 g
0.5805 g
5812.5 g

Explanation:

Step1: Convert volume to mL

We know that \(1\space L = 1000\space mL\). So, for \(V = 2.5\space L\), \(V=2.5\times1000 = 2500\space mL\)

Step2: Use mass/volume percentage formula

The mass/volume percentage formula is \(\text{mass/volume}\%=\frac{\text{mass of solute (g)}}{\text{volume of solution (mL)}}\times100\). Given \(\text{mass/volume}\% = 23.22\%\) and \(V = 2500\space mL\). Rearranging the formula for mass of solute \(m\): \(m=\frac{\text{mass/volume}\%\times V}{100}\)

Step3: Calculate the mass of solute

Substitute the values: \(m=\frac{23.22\times2500}{100}\). First, \(23.22\times2500=(23 + 0.22)\times2500=23\times2500+0.22\times2500 = 57500+ 550=58050\). Then \(\frac{58050}{100}=580.5\space g\)

Answer:

C. 580.5 g