Question

question 18 (1 point)
what is the electron configuration for a sodium ion?

1s²2s²2p⁴3s¹3p¹

1s²2s²2p⁶3s²

1s²2s²2p⁶3s¹

1s²2s²2p⁶

Explanation:

Sodium (\(Na\)) has an atomic number of \(11\). A sodium ion (\(Na^+\)) loses one electron. The electron configuration of neutral \(Na\) is \(1s^{2}2s^{2}2p^{6}3s^{1}\). When it loses the \(3s^{1}\) electron (to form a stable noble - gas - like configuration), the electron configuration becomes \(1s^{2}2s^{2}2p^{6}\).

Answer:

\(1s^{2}2s^{2}2p^{6}\) (the fourth option in the given choices)