Question

question 17 (1 point)
for each of the following pairs of molecules,
determine which is most polar:
c₂h₄ or c₂h₅oh
c₂h₆ or ch₃och₃
ccl₄ or cf₄
h₂o or h₂s
c₂h₄, c₂h₆, cf₄, hₛs
c₂h₅oh, ch₃och₃, ccl₄, hₛs
c₂h₅oh, ch₃och₃, cf₄, hₛs
c₂h₄, c₂h₆, cf₄, h₂o
c₂h₅oh, ch₃och₃, cf₄, h₂o

Explanation:

• For \(C_{2}H_{4}\) vs \(C_{2}H_{5}OH\): \(C_{2}H_{5}OH\) has a polar \(O - H\) bond (due to high electronegativity difference between \(O\) and \(H\)), while \(C_{2}H_{4}\) is non - polar (symmetrical structure).
• For \(C_{2}H_{6}\) vs \(CH_{3}OCH_{3}\): \(CH_{3}OCH_{3}\) has polar \(C - O\) bonds (electronegativity difference between \(C\) and \(O\)), \(C_{2}H_{6}\) is non - polar (only \(C - C\) and \(C - H\) bonds with small electronegativity differences).
• For \(CCl_{4}\) vs \(CF_{4}\): \(CF_{4}\) has more polar \(C - F\) bonds (greater electronegativity difference between \(C\) and \(F\) compared to \(C\) and \(Cl\)).
• For \(H_{2}O\) vs \(H_{2}S\): \(H_{2}O\) has more polar \(O - H\) bonds (greater electronegativity difference between \(O\) and \(H\) compared to \(S\) and \(H\)).

Answer:

\(C_{2}H_{5}OH, CH_{3}OCH_{3}, CF_{4}, H_{2}O\)