Question

question 14 (1 point)
a solution contains 0.90 g of sodium chloride dissolved in 100 ml of solution. the molar concentration of the solution is
0.9% (v/v)
526.6 m
0.90 g/100 ml
0.15 mol/l

Explanation:

Step1: Calculate the molar mass of NaCl

The molar mass of \(Na\) is \(22.99\ g/mol\) and the molar mass of \(Cl\) is \(35.45\ g/mol\). So, the molar mass of \(NaCl\), \(M = 22.99+35.45=58.44\ g/mol\).

Step2: Calculate the number of moles of NaCl

Given mass of \(NaCl\), \(m = 0.90\ g\). Using the formula \(n=\frac{m}{M}\), we have \(n=\frac{0.90\ g}{58.44\ g/mol}\approx0.0154\ mol\).

Step3: Convert the volume of the solution to liters

The volume of the solution \(V = 100\ mL=0.1\ L\).

Step4: Calculate the molar concentration (molarity)

Using the formula \(C=\frac{n}{V}\), we substitute \(n = 0.0154\ mol\) and \(V = 0.1\ L\). So, \(C=\frac{0.0154\ mol}{0.1\ L}=0.154\ mol/L\approx0.15\ mol/L\).

Answer:

0.15 mol/L