Question

question 11 (5 points)
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if the theoretical yield of a reaction is 332.5 g and the percent yield for the reaction is 38 percent, whats the actual yield of product in grams?
a) 8.74 g
b) 116.3 g
c) 12616 g
d) 126.4 g

Explanation:

Step1: Recall the percent yield formula

The formula for percent yield is $\text{Percent Yield} = \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \times 100\%$. We need to solve for Actual Yield, so rearranging the formula gives $\text{Actual Yield} = \frac{\text{Percent Yield} \times \text{Theoretical Yield}}{100\%}$.

Step2: Substitute the given values

We know the theoretical yield is $332.5\ \text{g}$ and the percent yield is $38\%$. Substituting these into the formula: $\text{Actual Yield} = \frac{38\% \times 332.5\ \text{g}}{100\%}$. First, convert $38\%$ to a decimal by dividing by 100, so $38\% = 0.38$. Then calculate $0.38 \times 332.5$.

Step3: Perform the multiplication

$0.38 \times 332.5 = 126.35\ \text{g}$, which rounds to $126.4\ \text{g}$ (or could be $126.3\ \text{g}$ depending on rounding during steps, but the closest option is D).

Answer:

D) 126.4 g