Question

question 10 (1 point)
calculate the density of oxygen at stp using the molar volume (22.414 l/mol) and the molar mass.
mass _1_ g
d = --------- = ------------ = _2_ g/l
volume _3_ l
a. 1.000 b. 273.15 c. 7.329 d. 22.414 e. 0.08205 l atm/mol k
f. 10.46 g. 1.428 h. 32.00 i. 4.000 j. 6.000 k. 2.000
l. 1.000 m. 298.15

Explanation:

Step1: Determine the molar mass of oxygen

The molar mass of \(O_2\) is \(32.00\) g/mol (since each \(O\) atom has a molar mass of \(16.00\) g/mol and there are 2 \(O\) atoms in \(O_2\)). So, the mass for 1 mole is \(32.00\) g.

Step2: Use the molar volume at STP

The molar volume at STP is given as \(22.414\) L/mol. So, the volume for 1 mole is \(22.414\) L.

Step3: Calculate the density

Density \(D=\frac{\text{mass}}{\text{volume}}\). Substituting the values, \(D = \frac{32.00\ \text{g}}{22.414\ \text{L}}\approx1.428\ \text{g/L}\)

Answer:

1. H. \(32.00\)
2. G. \(1.428\)
3. D. \(22.414\)