QUESTION IMAGE
Question
predict the products of the following reaction. if no reaction will occur, use the no reaction button.
be sure your chemical equation is balanced!
ch₃(ch₂)₃oh(l) + o₂(g) →
Step1: Determine the type of reaction
This is a combustion reaction of an alcohol. In complete combustion, alcohols react with oxygen (\(O_2\)) to produce carbon dioxide (\(CO_2\)) and water (\(H_2O\)). The general formula for the combustion of an alcohol \(C_nH_{2n + 2}O\) is \(C_nH_{2n+2}O+( \frac{3n}{2})O_2
ightarrow nCO_2+(n + 1)H_2O\). For \(CH_3(CH_2)_3OH\) (which is \(C_5H_{12}O\), \(n = 5\)):
Step2: Write the un - balanced equation
The un - balanced equation is \(C_5H_{12}O+O_2
ightarrow CO_2+H_2O\).
Step3: Balance the carbon atoms
There are 5 carbon atoms on the left. So, we put a 5 in front of \(CO_2\) on the right: \(C_5H_{12}O+O_2
ightarrow5CO_2+H_2O\).
Step4: Balance the hydrogen atoms
There are 12 hydrogen atoms on the left. So, we put a 6 in front of \(H_2O\) on the right: \(C_5H_{12}O+O_2
ightarrow5CO_2 + 6H_2O\).
Step5: Balance the oxygen atoms
On the right - hand side, the total number of oxygen atoms is \(5\times2+6\times1=16\). On the left - hand side, the alcohol (\(C_5H_{12}O\)) has 1 oxygen atom. Let the coefficient of \(O_2\) be \(x\). Then \(1 + 2x=16\), so \(2x=15\) and \(x=\frac{15}{2}\). Multiply each coefficient by 2 to get rid of the fraction: \(2C_5H_{12}O+15O_2
ightarrow10CO_2+12H_2O\).
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\(2CH_3(CH_2)_3OH(l)+15O_2(g)
ightarrow10CO_2(g)+12H_2O(l)\)