Question

part 4 (2 points)
choose one:
oxidation
reduction
+i₂(s)+6h₂o(l)→2io₃⁻+12h⁺(aq)+

Explanation:

Step1: Determine oxidation - states

In $I_2$, the oxidation - state of iodine is 0. In $IO_3^-$, the oxidation - state of iodine is +5.

Step2: Analyze oxidation - state change

The oxidation state of iodine changes from 0 in $I_2$ to +5 in $IO_3^-$. An increase in oxidation state indicates oxidation.

Answer:

Oxidation