Question

part a
give the correct formula for barium iodide.
express your answer as a chemical formula.
a chemical reaction does not occur for this question.

Explanation:

Step1: Determine ion charges

Barium (Ba) is in group 2, so it has a charge of \(+2\) (\(Ba^{2+}\)). Iodide (I⁻) is the anion of iodine, with a charge of \(-1\).

Step2: Balance charges

To form a neutral compound, the total positive charge must equal the total negative charge. Let the number of \(Ba^{2+}\) be \(x\) and \(I^-\) be \(y\). Then \(2x = y\) (since \(2(+1)=+2\) to balance \(+2\) from Ba). The smallest integers are \(x = 1\), \(y = 2\).

Step3: Write the formula

Combine the ions: \(Ba^{2+}\) and \(I^-\) form \(BaI_2\).

Answer:

\(BaI_2\)