Question

part c: draw a correct lewis structure for co₂.

Explanation:

Step1: Count valence electrons

Carbon has 4 valence electrons, and each oxygen has 6 valence electrons. So total valence electrons: \(4 + 2\times6=16\)

Step2: Arrange atoms

Carbon is the central atom (less electronegative than oxygen).

Step3: Distribute electrons

First, form single bonds (\(C - O\)). Each single bond uses 2 electrons. Then, distribute remaining electrons as lone pairs. But for \(CO_2\), the correct structure has double bonds. Carbon forms double bonds with each oxygen (\(O = C = O\)). Each oxygen has 2 lone pairs.

Answer:

\(O = C = O\) (with each oxygen having 2 lone pairs)