Question

part a
determine whether a homogeneous solution forms when each pair of substances is mixed.
check all that apply.
ch₃ch₂ch₂ch₂ch₃ and ch₃ch₂ch₂ch₂ch₃
cbr₄ and h₂o
cl₂ and h₂o
form a homogeneous solution when mixed.

Explanation:

• For \(CH_3CH_2CH_2CH_2CH_3\) and \(CH_3CH_2CH_2CH_2CH_2CH_3\): Both are non - polar hydrocarbons (alkanes). According to the "like dissolves like" principle, non - polar substances dissolve in non - polar solvents. So, they will form a homogeneous solution.
• For \(CBr_4\) and \(H_2O\): \(CBr_4\) is non - polar (symmetrical tetrahedral structure) and \(H_2O\) is polar. Non - polar and polar substances do not mix well (violate the "like dissolves like" principle), so they will not form a homogeneous solution.
• For \(Cl_2\) and \(H_2O\): \(Cl_2\) is non - polar (a diatomic non - polar molecule) and \(H_2O\) is polar. Non - polar and polar substances do not mix well (violate the "like dissolves like" principle), so they will not form a homogeneous solution.

Answer:

\(CH_3CH_2CH_2CH_2CH_3\) and \(CH_3CH_2CH_2CH_2CH_2CH_3\)