Question

part b
correct the false sentences from the part a.
the ( mathrm{fe}^{2+} ) ion contains 26 protons and 29 electrons.
the ( mathrm{fe}^{2+} ) ion contains 26 protons and 24 electrons.
the ( mathrm{fe}^{2+} ) ion contains 29 protons and 32 electrons.
the ( mathrm{fe}^{2+} ) ion contains 29 protons and 23 electrons.

Explanation:

Step1: Determine the number of protons

The atomic number of iron (Fe) is 26. The number of protons in an atom or ion is equal to its atomic number. So, for \(Fe^{2 +}\), the number of protons \(p = 26\).

Step2: Calculate the number of electrons

For a neutral atom, the number of electrons \(e\) is equal to the number of protons. For a cation \(M^{n+}\), the number of electrons \(e=p - n\). Here, \(n = 2\) (since it is \(Fe^{2+}\)), so \(e=26 - 2=24\).

Answer:

The \(Fe^{2+}\) ion contains 26 protons and 24 electrons.