Question

part b
c4h10(g) + o2(g) →
express your answer as a complete chemical equation including phases.
a chemical reaction does not occur for this question.

Explanation:

Step1: Balance carbon atoms

The reactant \(C_4H_{10}\) has 4 carbon atoms. On the product side, \(CO_2\) contains carbon. To balance carbon, we put a coefficient of 4 in front of \(CO_2\).
\(C_4H_{10}(g)+O_2(g)\to4CO_2(g)+H_2O(l)\)

Step2: Balance hydrogen atoms

The reactant \(C_4H_{10}\) has 10 hydrogen atoms. On the product side, \(H_2O\) contains hydrogen. To balance hydrogen, we put a coefficient of 5 in front of \(H_2O\).
\(C_4H_{10}(g)+O_2(g)\to4CO_2(g)+5H_2O(l)\)

Step3: Balance oxygen atoms

On the product side, we have \(4\times2 + 5\times1=8 + 5 = 13\) oxygen atoms in \(4CO_2\) and \(5H_2O\). On the reactant side, \(O_2\) provides oxygen. To balance oxygen, we put a coefficient of \(\frac{13}{2}\) in front of \(O_2\). But we usually prefer whole - number coefficients. So we multiply the entire equation by 2.

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Answer:

\(2C_4H_{10}(g)+13O_2(g)\to8CO_2(g)+10H_2O(l)\)