Question

part 1 atomic structure
practice: atomic calculations

1. draw five protons in the atom to the right. label them with their charge.
2. draw six neutrons in the atom to the right. label them with their charge.
3. draw five electrons in the atom to the right. place two on the first energy level

and three on the second. label them with their charge.

1. what element did you just draw?
2. how do you know?

part 2 periodic table

1. label each part of the periodic table notation shown to the right.
2. how do you know the number of protons in an atom?
3. how do you know the number of neutrons?
4. how do you know the number of electrons?

part 3 atomic calculations: complete the chart below.
10.
element atomic # mass # # of p+ # of n0 # of e-
3 7
p 31
1 1
25 30
k 39
ag 61
35 17
si 14
74 110
10 10

Explanation:

Step1: Recall atomic structure relationships

• Atomic number (\(Z\)) = number of protons (\(\#\text{ of }p^{+}\))
• Mass number (\(A\)) = number of protons + number of neutrons (\(\#\text{ of }n^{0}\))
• For neutral atoms, number of electrons (\(\#\text{ of }e^{-}\)) = number of protons

Step2: Fill the first row (Atomic \(\# = 3\), Mass \(\#=7\))

• \(\#\text{ of }p^{+}=3\) (from atomic number)
• \(\#\text{ of }n^{0}=A - Z=7 - 3 = 4\)
• \(\#\text{ of }e^{-}=3\) (neutral atom)

Step3: Fill the row for \(P\) (Phosphorus)

• Atomic number of \(P\) from periodic table is \(15\) (\(\#\text{ of }p^{+}=15\))
• \(\#\text{ of }n^{0}=31 - 15=16\)
• \(\#\text{ of }e^{-}=15\)

Step4: Fill the row with \(\#\text{ of }p^{+}=1\), Mass \(\# = 1\)

• Element is \(H\) (Hydrogen)
• \(\#\text{ of }n^{0}=1 - 1=0\)
• \(\#\text{ of }e^{-}=1\)

Step5: Fill the row with Atomic \(\# = 25\), \(\#\text{ of }n^{0}=30\)

• \(\#\text{ of }p^{+}=25\)
• Mass \(\#=25 + 30=55\)
• \(\#\text{ of }e^{-}=25\)

Step6: Fill the row for \(K\) (Potassium)

• Atomic number of \(K\) from periodic table is \(19\) (\(\#\text{ of }p^{+}=19\))
• \(\#\text{ of }n^{0}=39 - 19 = 20\)
• \(\#\text{ of }e^{-}=19\)

Step7: Fill the row for \(Ag\) (Silver)

• Atomic number of \(Ag\) from periodic table is \(47\) (\(\#\text{ of }p^{+}=47\))
• Mass \(\#=47+61 = 108\)
• \(\#\text{ of }e^{-}=47\)

Step8: Fill the row with \(\#\text{ of }p^{+}=17\), Mass \(\# = 35\)

• Element is \(Cl\) (Chlorine)
• \(\#\text{ of }n^{0}=35 - 17=18\)
• \(\#\text{ of }e^{-}=17\)

Step9: Fill the row for \(Si\) (Silicon)

• Atomic number of \(Si\) from periodic table is \(14\) (\(\#\text{ of }p^{+}=14\))
• Mass \(\#=14 + 14=28\)
• \(\#\text{ of }e^{-}=14\)

Step10: Fill the row with \(\#\text{ of }p^{+}=74\), \(\#\text{ of }n^{0}=110\)

• Mass \(\#=74+110 = 184\)
• Element is \(W\) (Tungsten)
• \(\#\text{ of }e^{-}=74\)

Step11: Fill the last row (\(\#\text{ of }n^{0}=10\), \(\#\text{ of }e^{-}=10\))

• \(\#\text{ of }p^{+}=10\)
• Atomic number \(Z = 10\) (Neon, \(Ne\))
• Mass \(\#=10 + 10=20\)

Answer:

Element	Atomic \(\#\)	Mass \(\#\)	\(\#\text{ of }p^{+}\)	\(\#\text{ of }n^{0}\)	\(\#\text{ of }e^{-}\)
\(P\)	\(15\)	\(31\)	\(15\)	\(16\)	\(15\)
\(H\)	\(1\)	\(1\)	\(1\)	\(0\)	\(1\)
\(Mn\)	\(25\)	\(55\)	\(25\)	\(30\)	\(25\)
\(K\)	\(19\)	\(39\)	\(19\)	\(20\)	\(19\)
\(Ag\)	\(47\)	\(108\)	\(47\)	\(61\)	\(47\)
\(Cl\)	\(17\)	\(35\)	\(17\)	\(18\)	\(17\)
\(Si\)	\(14\)	\(28\)	\(14\)	\(14\)	\(14\)
\(W\)	\(74\)	\(184\)	\(74\)	\(110\)	\(74\)
\(Ne\)	\(10\)	\(20\)	\(10\)	\(10\)	\(10\)