Question

1. one of the reactions you balanced in part 1 contained the compound aluminum sulfate al2(so4)3. how many moles of oxygen are present in the entire aluminum sulfate substance? (1 pt)
2. given 0.148 moles of al2(so4)3, how many moles of oxygen are present in the substance? (3 pts total: 2 pts for answer with units; 1 pt for work)
3. given avogadros number (na = 6.022 × 10²³ particles = 1 mole) and 0.148 moles of al2(so4)3, how many atoms of oxygen are present in the substance? (4 pts total: 2 pts for answer with units; 2 pts for work)

Explanation:

Step1: Determine the number of oxygen atoms in one molecule of \(Al_2(SO_4)_3\)

In \(Al_2(SO_4)_3\), there are \(4\times3 = 12\) oxygen atoms per molecule.

Step2: Calculate the moles of oxygen

Given \(0.148\) moles of \(Al_2(SO_4)_3\), the moles of oxygen \(n = 0.148\times12=1.776\) moles.

Answer:

\(1.776\) moles