QUESTION IMAGE
Question
the octet rule
- atoms are most stable when they have a full outer shell of valence electrons.
- most atoms will attempt to have a full outer shell of eight valence electrons.
- atoms will gain or lose electrons to fulfill the octet rule.
- atoms seek to gain or lose the fewest electrons possible in becoming stable.
example: draw a lewis dot structure for each element below. indicate whether the
element will gain or lose electrons to have a full outer shell, and identify how many
electrons it will gain or lose.
bromine calcium
lithium oxygen
Bromine
Step1: Determine valence electrons
Bromine (Br) is in group 17. Valence electrons = 7. Lewis dot structure: $\cdot \cdot \cdot \cdot \cdot \cdot \cdot$ (7 dots around Br symbol).
Step2: Analyze electron gain/loss
To reach octet (8 electrons), it needs 1 electron. So, it will gain 1 electron.
Calcium
Step1: Determine valence electrons
Calcium (Ca) is in group 2. Valence electrons = 2. Lewis dot structure: $\cdot \cdot$ (2 dots around Ca symbol).
Step2: Analyze electron gain/loss
To reach octet, losing 2 electrons (easier than gaining 6). So, it will lose 2 electrons.
Lithium
Step1: Determine valence electrons
Lithium (Li) is in group 1. Valence electrons = 1. Lewis dot structure: $\cdot$ (1 dot around Li symbol).
Step2: Analyze electron gain/loss
To reach octet (for Li, a full outer shell can be 2 electrons as it's in period 1, but following octet rule concept here), losing 1 electron (easier than gaining 7). So, it will lose 1 electron.
Oxygen
Step1: Determine valence electrons
Oxygen (O) is in group 16. Valence electrons = 6. Lewis dot structure: $\cdot \cdot \cdot \cdot \cdot \cdot$ (6 dots around O symbol).
Step2: Analyze electron gain/loss
To reach octet, it needs 2 electrons. So, it will gain 2 electrons.
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- Bromine: Lewis dot structure with 7 dots, gains 1 electron.
- Calcium: Lewis dot structure with 2 dots, loses 2 electrons.
- Lithium: Lewis dot structure with 1 dot, loses 1 electron.
- Oxygen: Lewis dot structure with 6 dots, gains 2 electrons.