Question

3 numeric 1 point an unknown gas has a volume of 17 l, a temperature of 67°c, and a pressure of 88.8 atm. what will be the new pressure of the gas be if the temperature is raised to 94°c, and the volume is decreased to 12 l. round to 3 sig figs. do not include units. answer previous next

Explanation:

Step1: Convert temperatures to Kelvin

$$T_1 = 67 + 273=340\ K$$
$$T_2 = 94 + 273 = 367\ K$$

Step2: Use the combined gas law $\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

We know $P_1 = 88.8$, $V_1 = 17$, $T_1 = 340$, $V_2 = 12$, $T_2 = 367$. Rearrange for $P_2$:
$$P_2=\frac{P_1V_1T_2}{V_2T_1}$$

Step3: Substitute values

$$P_2=\frac{88.8\times17\times367}{12\times340}$$
First calculate numerator: $88.8\times17\times367 = 88.8\times6239=554023.2$
Then calculate denominator: $12\times340 = 4080$
$$P_2=\frac{554023.2}{4080}=135.79$$

Answer:

$136$