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nitrogen dioxide is a gas commonly found in polluted air. it is produce…

Question

nitrogen dioxide is a gas commonly found in polluted air. it is produced when nitric oxide in the air reacts with oxygen gas. consider the following reaction: 6 molecules of nitric oxide (no) react with 3 molecules of oxygen (o₂) to produce some amount of nitrogen dioxide (no₂). complete the table below. chemical element | number of atoms in the reaction n | o | during this reaction, how many molecules of nitrogen dioxide (no₂) are produced?

Explanation:

Part 1: Number of N and O atoms in the reaction
Step 1: Calculate number of N atoms

Each NO molecule has 1 N atom. There are 6 NO molecules. So number of N atoms = \( 6 \times 1 = 6 \).

Step 2: Calculate number of O atoms
  • From NO: Each NO has 1 O atom, 6 NO molecules give \( 6 \times 1 = 6 \) O atoms.
  • From \( O_2 \): Each \( O_2 \) has 2 O atoms, 3 \( O_2 \) molecules give \( 3 \times 2 = 6 \) O atoms.
  • Total O atoms = \( 6 + 6 = 12 \).
Part 2: Number of \( NO_2 \) molecules produced
Step 1: Write the balanced chemical equation

The reaction is \( 2NO + O_2
ightarrow 2NO_2 \) (simplified from 6 NO and 3 \( O_2 \), divide by 3: \( 2NO + O_2
ightarrow 2NO_2 \)). For 6 NO (which is 3 times 2 NO) and 3 \( O_2 \) (3 times 1 \( O_2 \)), the moles of \( NO_2 \) produced will be 3 times 2, so 6.

Alternatively, using atom conservation:

  • Each \( NO_2 \) has 1 N and 2 O.
  • We have 6 N atoms, so number of \( NO_2 \) molecules from N: \( \frac{6}{1} = 6 \).
  • We have 12 O atoms, number of \( NO_2 \) molecules from O: \( \frac{12}{2} = 6 \). So 6 molecules of \( NO_2 \) are produced.
Final Answers
  • Number of N atoms: \( \boldsymbol{6} \)
  • Number of O atoms: \( \boldsymbol{12} \)
  • Number of \( NO_2 \) molecules: \( \boldsymbol{6} \)

Answer:

Part 1: Number of N and O atoms in the reaction
Step 1: Calculate number of N atoms

Each NO molecule has 1 N atom. There are 6 NO molecules. So number of N atoms = \( 6 \times 1 = 6 \).

Step 2: Calculate number of O atoms
  • From NO: Each NO has 1 O atom, 6 NO molecules give \( 6 \times 1 = 6 \) O atoms.
  • From \( O_2 \): Each \( O_2 \) has 2 O atoms, 3 \( O_2 \) molecules give \( 3 \times 2 = 6 \) O atoms.
  • Total O atoms = \( 6 + 6 = 12 \).
Part 2: Number of \( NO_2 \) molecules produced
Step 1: Write the balanced chemical equation

The reaction is \( 2NO + O_2
ightarrow 2NO_2 \) (simplified from 6 NO and 3 \( O_2 \), divide by 3: \( 2NO + O_2
ightarrow 2NO_2 \)). For 6 NO (which is 3 times 2 NO) and 3 \( O_2 \) (3 times 1 \( O_2 \)), the moles of \( NO_2 \) produced will be 3 times 2, so 6.

Alternatively, using atom conservation:

  • Each \( NO_2 \) has 1 N and 2 O.
  • We have 6 N atoms, so number of \( NO_2 \) molecules from N: \( \frac{6}{1} = 6 \).
  • We have 12 O atoms, number of \( NO_2 \) molecules from O: \( \frac{12}{2} = 6 \). So 6 molecules of \( NO_2 \) are produced.
Final Answers
  • Number of N atoms: \( \boldsymbol{6} \)
  • Number of O atoms: \( \boldsymbol{12} \)
  • Number of \( NO_2 \) molecules: \( \boldsymbol{6} \)