Question

1. __n₂ + h₂ → __nh₃

Explanation:

Step1: Balance nitrogen atoms

On the left - hand side, there are \(2\) nitrogen atoms in \(N_{2}\), and on the right - hand side, there is \(1\) nitrogen atom in \(NH_{3}\). So, we put a coefficient of \(2\) in front of \(NH_{3}\): \(N_{2}+H_{2}\to2NH_{3}\)

Step2: Balance hydrogen atoms

Now, on the right - hand side, there are \(2\times3 = 6\) hydrogen atoms in \(2NH_{3}\). On the left - hand side, there are \(2\) hydrogen atoms in \(H_{2}\). So, we put a coefficient of \(3\) in front of \(H_{2}\): \(N_{2}+3H_{2}\to2NH_{3}\)

Answer:

\(1N_{2}+3H_{2}\to2NH_{3}\)