Question

7 multiple choice 6 points
name the following compound: fei₂
iron iodine
iron (ii) iodide
iron iodide
iron (iii) iodide
8 multiple choice 6 points
name the following compound: cdo
cadmium (ii) oxide
carbon dioxide
cadmium oxide
cadmium oxygen
9 multiple choice 6 points
name the following compound: aucl
silver (i) chloride
gold (i) chloride
gold (ii) chloride
silver chloride

Explanation:

• For \(FeI_2\): Iron (\(Fe\)) can have multiple oxidation states. In \(FeI_2\), iodine (\(I\)) has an oxidation state of \(- 1\). Let the oxidation state of \(Fe\) be \(x\). Using the formula \(x + 2\times(-1)=0\) (since the compound is neutral), we get \(x = + 2\). So it is iron (II) iodide.
• For \(CdO\): Cadmium (\(Cd\)) has a common oxidation state. Oxygen (\(O\)) has an oxidation state of \(-2\). Let the oxidation state of \(Cd\) be \(y\). Using \(y+(-2) = 0\), we get \(y=+2\). But for simple ionic compounds where the metal has a single common oxidation state (like \(Cd\) here, which mainly forms \(Cd^{2 +}\) in such binary compounds), we can name it as cadmium oxide.
• For \(AuCl\): Gold (\(Au\)) can have different oxidation states. Chlorine (\(Cl\)) has an oxidation state of \(-1\). Let the oxidation state of \(Au\) be \(z\). Using \(z+(-1)=0\), we get \(z = + 1\). So it is gold (I) chloride.

Answer:

1. iron (II) iodide
2. cadmium oxide
3. gold (I) chloride