Question

1 multiple choice 2 points
balance the following equation.
_alcl₃→_al + ___cl₂
2alcl₃→1al + 3cl₂
1alcl₃→1al + 1cl₂
3alcl₃→1al + 2cl₂
2alcl₃→2al + 3cl₂

Explanation:

Step1: Count atoms on both sides

For \(AlCl_3\), there is 1 \(Al\) atom and 3 \(Cl\) atoms. For \(Al\), there is 1 \(Al\) atom. For \(Cl_2\), there are 2 \(Cl\) atoms.

Step2: Balance \(Cl\) atoms

To balance \(Cl\) atoms, find the least - common multiple of 3 and 2, which is 6. So we need 2 \(AlCl_3\) (gives \(2\times3 = 6\) \(Cl\) atoms) and 3 \(Cl_2\) (gives \(3\times2=6\) \(Cl\) atoms).

Step3: Balance \(Al\) atoms

Since we have 2 \(AlCl_3\), we need 2 \(Al\) atoms on the right - hand side.

Answer:

\(2AlCl_3
ightarrow2Al + 3Cl_2\) (the fourth option)