Question

8 multiple choice 10 points what is the name for pbbr₄? lead (iv) bromine lead (iv) bromide lead (i) bromide lead bromide

Explanation:

• Identify the metal and non - metal: In \(PbBr_4\), \(Pb\) is lead (a metal) and \(Br\) is bromine (a non - metal). When naming ionic compounds, the non - metal part (bromine) is changed to “bromide”.
• Determine the oxidation state of lead: In \(PbBr_4\), bromide (\(Br^-\)) has an oxidation state of \(- 1\). Let the oxidation state of \(Pb\) be \(x\). Using the charge balance in the compound \(x+4\times(-1)=0\), so \(x = + 4\). In the naming of ionic compounds with metals that have variable oxidation states (lead is such a metal), we use Roman numerals in parentheses to denote the oxidation state of the metal.

Answer:

lead (IV) bromide (the second option in the multiple - choice list)