Question

if i have 2.7 moles of gas at a pressure of 0.8 atm and at a temperature of 320k, what is the volume of the container that the gas is in?

$p\times v = n\times r\times t$

$r = 0.0821$

a 7.4 l
b 98 l
c 49.8 l
d.97 l

Explanation:

Step1: Rearrange the ideal gas law formula

The ideal gas law is \(PV = nRT\). We want to solve for \(V\), so we rearrange the formula to \(V=\frac{nRT}{P}\).

Step2: Substitute the given values

We are given \(n = 2.7\) moles, \(R=0.0821\space L\cdot atm/(mol\cdot K)\), \(T = 320\space K\), and \(P=0.8\space atm\).
Substituting these values into the formula:

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Answer:

B. 98 L