Question

the molecule has 2 bonding domains. what is the vsepr geometry of this molecule? linear tetrahedral trigonal pyramidal trigonal planar

Explanation:

According to VSEPR theory, when a molecule has 2 bonding domains and no lone pairs (as in \(H - C\equiv N\)), the geometry is linear. The two bonding domains ( \(H - C\) and \(C\equiv N\)) arrange themselves to be as far apart as possible, which in 3 - D space corresponds to a \(180^{\circ}\) angle, characteristic of linear geometry. Tetrahedral geometry occurs with 4 bonding domains (e.g., \(CH_4\)), trigonal pyramidal with 3 bonding and 1 lone pair (e.g., \(NH_3\)), and trigonal planar with 3 bonding domains (e.g., \(BF_3\)).

Answer:

linear