7. molecular compounds
1. write the formula
a) diphosphorus trioxide
b) sulfur hexafluoride
c) dichlorine monoxide
d) iodine gas
2. write the name
a) n₂o₂
b) pcl₅
c) co
d) h₂o
8. show how a compound forms between the following pairs of elements.
a) ca + f
b) li + o

Question

7. molecular compounds
1. write the formula
a) diphosphorus trioxide
 b) sulfur hexafluoride
 c) dichlorine monoxide
 d) iodine gas
2. write the name
a) n₂o₂
 b) pcl₅
 c) co
 d) h₂o
8. show how a compound forms between the following pairs of elements.
a) ca + f
b) li + o

Accepted Answer

# 7. Molecular Compounds
## 1. Write the formula
### a) diphosphorus trioxide
# Explanation:
## Step1: Analyze prefixes
The prefix "di - " means 2 (for phosphorus, $P$) and "tri - " means 3 (for oxygen, $O$).
## Step2: Write the formula
Based on the prefixes, the formula is $P_{2}O_{3}$.

### b) sulfur hexafluoride
# Explanation:
## Step1: Analyze prefixes
The prefix "hexa - " means 6 (for fluorine, $F$), and sulfur is $S$.
## Step2: Write the formula
Based on the prefixes, the formula is $SF_{6}$.

### c) dichlorine monoxide
# Explanation:
## Step1: Analyze prefixes
The prefix "di - " means 2 (for chlorine, $Cl$) and "mono - " means 1 (for oxygen, $O$).
## Step2: Write the formula
Based on the prefixes, the formula is $Cl_{2}O$.

### d) iodine gas
# Explanation:
## Step1: Consider diatomic nature
Iodine gas is a diatomic molecule.
## Step2: Write the formula
The formula is $I_{2}$.

## 2. Write the name
### a) $N_{2}O_{2}$
# Explanation:
## Step1: Identify elements and prefixes
$N$ is nitrogen, $O$ is oxygen. There are 2 $N$ (prefix "di - ") and 2 $O$ (prefix "di - ").
## Step2: Name the compound
The name is dinitrogen dioxide.

### b) $PCl_{5}$
# Explanation:
## Step1: Identify elements and prefixes
$P$ is phosphorus, $Cl$ is chlorine. There is 1 $P$ (no prefix as it's the first element) and 5 $Cl$ (prefix "penta - ").
## Step2: Name the compound
The name is phosphorus pentachloride.

### c) $CO$
# Explanation:
## Step1: Identify elements and prefixes
$C$ is carbon, $O$ is oxygen. There is 1 $C$ (no prefix as it's the first element) and 1 $O$ (prefix "mono - ").
## Step2: Name the compound
The name is carbon monoxide.

### d) $H_{2}O$
# Explanation:
## Step1: Use common name
$H_{2}O$ has a common name.
## Step2: Name the compound
The common name is water.

# 8. Show how a compound forms between the following pairs of elements
## a) $Ca+F$
# Explanation:
## Step1: Determine charges
Calcium ($Ca$) has a charge of $+ 2$ ($Ca^{2+}$), fluorine ($F$) has a charge of $-1$ ($F^{-}$).
## Step2: Balance charges
To balance the charges, we need 2 $F^{-}$ for 1 $Ca^{2+}$.
## Step3: Write the formula
The formula is $CaF_{2}$.

## b) $Li + O$
# Explanation:
## Step1: Determine charges
Lithium ($Li$) has a charge of $+1$ ($Li^{+}$), oxygen ($O$) has a charge of $-2$ ($O^{2 - }$).
## Step2: Balance charges
To balance the charges, we need 2 $Li^{+}$ for 1 $O^{2-}$.
## Step3: Write the formula
The formula is $Li_{2}O$.

# Answer:
## 7. Molecular Compounds
### 1. Write the formula
a) $P_{2}O_{3}$
b) $SF_{6}$
c) $Cl_{2}O$
d) $I_{2}$
### 2. Write the name
a) dinitrogen dioxide
b) phosphorus pentachloride
c) carbon monoxide
d) water
## 8. Show how a compound forms between the following pairs of elements
a) $CaF_{2}$
b) $Li_{2}O$

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QUESTION IMAGE

Question

Explanation:

7. Molecular Compounds

1. Write the formula

a) diphosphorus trioxide

Step1: Analyze prefixes

Step2: Write the formula

b) sulfur hexafluoride

Step1: Analyze prefixes

Step2: Write the formula

c) dichlorine monoxide

Step1: Analyze prefixes

Step2: Write the formula

d) iodine gas

Answer:

7. Molecular Compounds

1. Write the formula

2. Write the name

8. Show how a compound forms between the following pairs of elements