Question

1. molecular compounds
2. write the formula

a) diphosphorus trioxide
b) sulfur hexafluoride
c) dichlorine monoxide
d) lodine gas

Explanation:

Step1: Analyze prefixes and elements

• Diphosphorus trioxide: "di - " means 2, so 2 phosphorus ($P$) atoms. "tri - " means 3, so 3 oxygen ($O$) atoms.
• Sulfur hexafluoride: "hexa - " means 6, so 6 fluorine ($F$) atoms. 1 sulfur ($S$) atom.
• Dichlorine monoxide: "di - " means 2, so 2 chlorine ($Cl$) atoms. "mono - " means 1, so 1 oxygen ($O$) atom.
• Iodine gas: Iodine gas is a diatomic molecule, so 2 iodine ($I$) atoms.

Step2: Write formulas

• For diphosphorus trioxide: $P_2O_3$
• For sulfur hexafluoride: $SF_6$
• For dichlorine monoxide: $Cl_2O$
• For iodine gas: $I_2$

Answer:

a) $P_2O_3$
b) $SF_6$
c) $Cl_2O$
d) $I_2$