Question

the molar mass of nh3 is 17.04 g/mol. what is the percent n in nh3? (h = 1.01 g/mol, n = 14.01 amu) % comp. n = \frac{mass n}{mass of sample} × 100 ?% n

Explanation:

Step1: Identify the mass of N

The mass of N in \(NH_3\) is \(14.01\) g (since there is 1 N atom in \(NH_3\)).

Step2: Use the percentage composition formula

The formula for percentage composition of \(N\) is \(\%\text{comp. }N=\frac{\text{mass }N}{\text{mass of sample}}\times100\).
Substitute the values: \(\%\text{comp. }N=\frac{14.01}{17.04}\times 100\).
Calculate \(\frac{14.01}{17.04}\approx0.8222\).
Then \(0.8222\times100 = 82.22\).

Answer:

\(82.22\%\)