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mg + 2hcl → mgcl₂ + h₂ (mg: 24.3 g/mol) the number of moles of gas need…

Question

mg + 2hcl → mgcl₂ + h₂
(mg: 24.3 g/mol)
the number of moles of gas needed
to fill a container was calculated to
be 0.16 mol h₂. what mass of mg is
required to generate the h₂ gas?
? g mg
hint: use stoichiometry.
mass mg (g)
submit

Explanation:

Step1: Find mole ratio of Mg to H₂

From reaction: 1 mol Mg → 1 mol H₂, ratio = 1:1

Step2: Calculate moles of Mg

Moles of Mg = moles of H₂ = 0.16 mol

Step3: Compute mass of Mg

Mass = moles × molar mass = 0.16 mol × 24.3 g/mol = 3.888 g

Answer:

3.89 (rounded to two decimal places) or 3.888 g